Every arrow of length 5
Needs: this page (length from components).
The arrow (3, 4) has length 5. How many different vectors with whole-number components have length exactly 5? Count every sign and every order: (3, 4) and (4, 3) are different vectors.
Hint 1
Write the length rule as an equation: x² + y² = 25, where x and y are whole numbers, positive, negative or zero.
Hint 2
Try each size of x from 0 to 5 and ask whether 25 − x² is a perfect square.
Hint 3
Sizes 0 and 5 give arrows along the axes. Sizes 3 and 4 give slanted arrows. Each slanted solution has four sign versions.
Hints used: 0 of 3
Solution
x² + y² = 25 has whole-number solutions only when |x| is 0, 3, 4 or 5. |x| = 0 gives y = ±5, and |x| = 5 gives y = 0: four arrows along the axes. x = ±3 with y = ±4, and x = ±4 with y = ±3: eight slanted arrows. In total 4 + 8 = 12.
The eight slanted arrows are the opening figure's (3, 4), turned and reflected: the same length in eight directions. Length alone could not tell them apart, which is the point of Plate 1.1.